Adam has 4 times as many red stickers as blue stickers.
After he gives away 31 blue stickers,
Adam has 5 times as many red stickers as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Red |
Blue |
Before |
4 x 5 = 20 u |
1 x 5 = 5 u |
Change |
No Change |
- 31 |
After |
5 x 4 = 20 u |
1 x 4 = 4 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and blue stickers the same using LCM of 4 and 5.
LCM of 4 and 5 = 20
Number of blue stickers that Adam gives away
= 5 u - 4 u
= 1 u
1 u = 31
Number of more red stickers than blue stickers at first
= 20 u - 5 u
= 15 u
= 15 x 31
= 465
(b)
Number of less blue stickers than red stickers in the end
= 20 u - 4 u
= 16 u
= 16 x 31
= 496
Answer(s): (a) 465; (b) 496