Adam has 2 times as many green stickers as red stickers.
After he gives away 33 red stickers,
Adam has 5 times as many green stickers as red stickers.
- How many more green stickers than red stickers does Adam have at first?
- How many less red stickers than green stickers does Adam have in the end?
|
Green |
Red |
Before |
2 x 5 = 10 u |
1 x 5 = 5 u |
Change |
No Change |
- 33 |
After |
5 x 2 = 10 u |
1 x 2 = 2 u |
(a)
The number of green stickers remains unchanged.
Make the number of green stickers and red stickers the same using LCM of 2 and 5.
LCM of 2 and 5 = 10
Number of red stickers that Adam gives away
= 5 u - 2 u
= 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
Number of more green stickers than red stickers at first
= 10 u - 5 u
= 5 u
= 5 x 11
= 55
(b)
Number of less red stickers than green stickers in the end
= 10 u - 2 u
= 8 u
= 8 x 11
= 88
Answer(s): (a) 55; (b) 88