Adam has 3 times as many green stickers as blue stickers.
After he gives away 33 blue stickers,
Adam has 4 times as many green stickers as blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many less blue stickers than green stickers does Adam have in the end?
|
Green |
Blue |
Before |
3 x 4 = 12 u |
1 x 4 = 4 u |
Change |
No Change |
- 33 |
After |
4 x 3 = 12 u |
1 x 3 = 3 u |
(a)
The number of green stickers remains unchanged.
Make the number of green stickers and blue stickers the same using LCM of 3 and 4.
LCM of 3 and 4 = 12
Number of blue stickers that Adam gives away
= 4 u - 3 u
= 1 u
1 u = 33
Number of more green stickers than blue stickers at first
= 12 u - 4 u
= 8 u
= 8 x 33
= 264
(b)
Number of less blue stickers than green stickers in the end
= 12 u - 3 u
= 9 u
= 9 x 33
= 297
Answer(s): (a) 264; (b) 297