Adam has 4 times as many green stickers as blue stickers.
After he gives away 42 blue stickers,
Adam has 6 times as many green stickers as blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many less blue stickers than green stickers does Adam have in the end?
|
Green |
Blue |
Before |
4 x 3 = 12 u |
1 x 3 = 3 u |
Change |
No Change |
- 42 |
After |
6 x 2 = 12 u |
1 x 2 = 2 u |
(a)
The number of green stickers remains unchanged.
Make the number of green stickers and blue stickers the same using LCM of 4 and 6.
LCM of 4 and 6 = 12
Number of blue stickers that Adam gives away
= 3 u - 2 u
= 1 u
1 u = 42
1 u = 42 ÷ 1 = 42
Number of more green stickers than blue stickers at first
= 12 u - 6 u
= 6 u
= 6 x 42
= 252
(b)
Number of less blue stickers than green stickers in the end
= 12 u - 4 u
= 8 u
= 8 x 42
= 336
Answer(s): (a) 252; (b) 336