Adam has 3 times as many red stickers as blue stickers.
After he gives away 30 blue stickers,
Adam has 4 times as many red stickers as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Red |
Blue |
Before |
3 x 4 = 12 u |
1 x 4 = 4 u |
Change |
No Change |
- 30 |
After |
4 x 3 = 12 u |
1 x 3 = 3 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and blue stickers the same using LCM of 3 and 4.
LCM of 3 and 4 = 12
Number of blue stickers that Adam gives away
= 4 u - 3 u
= 1 u
1 u = 30
Number of more red stickers than blue stickers at first
= 12 u - 4 u
= 8 u
= 8 x 30
= 240
(b)
Number of less blue stickers than red stickers in the end
= 12 u - 3 u
= 9 u
= 9 x 30
= 270
Answer(s): (a) 240; (b) 270