Adam has 3 times as many blue stickers as green stickers.
After he gives away 25 green stickers,
Adam has 4 times as many blue stickers as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
3 x 4 = 12 u |
1 x 4 = 4 u |
Change |
No Change |
- 25 |
After |
4 x 3 = 12 u |
1 x 3 = 3 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and green stickers the same using LCM of 3 and 4.
LCM of 3 and 4 = 12
Number of green stickers that Adam gives away
= 4 u - 3 u
= 1 u
1 u = 25
Number of more blue stickers than green stickers at first
= 12 u - 4 u
= 8 u
= 8 x 25
= 200
(b)
Number of less green stickers than blue stickers in the end
= 12 u - 3 u
= 9 u
= 9 x 25
= 225
Answer(s): (a) 200; (b) 225