Adam has 2 times as many blue stickers as green stickers.
After he gives away 30 green stickers,
Adam has 7 times as many blue stickers as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
2 x 7 = 14 u |
1 x 7 = 7 u |
Change |
No Change |
- 30 |
After |
7 x 2 = 14 u |
1 x 2 = 2 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and green stickers the same using LCM of 2 and 7.
LCM of 2 and 7 = 14
Number of green stickers that Adam gives away
= 7 u - 2 u
= 5 u
5 u = 30
1 u = 30 ÷ 5 = 6
Number of more blue stickers than green stickers at first
= 14 u - 7 u
= 7 u
= 7 x 6
= 42
(b)
Number of less green stickers than blue stickers in the end
= 14 u - 2 u
= 12 u
= 12 x 6
= 72
Answer(s): (a) 42; (b) 72