Adam has 3 times as many red stickers as green stickers.
After he gives away 32 green stickers,
Adam has 4 times as many red stickers as green stickers.
- How many more red stickers than green stickers does Adam have at first?
- How many less green stickers than red stickers does Adam have in the end?
|
Red |
Green |
Before |
3 x 4 = 12 u |
1 x 4 = 4 u |
Change |
No Change |
- 32 |
After |
4 x 3 = 12 u |
1 x 3 = 3 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and green stickers the same using LCM of 3 and 4.
LCM of 3 and 4 = 12
Number of green stickers that Adam gives away
= 4 u - 3 u
= 1 u
1 u = 32
Number of more red stickers than green stickers at first
= 12 u - 4 u
= 8 u
= 8 x 32
= 256
(b)
Number of less green stickers than red stickers in the end
= 12 u - 3 u
= 9 u
= 9 x 32
= 288
Answer(s): (a) 256; (b) 288