Adam has 3 times as many red stickers as blue stickers.
After he gives away 25 blue stickers,
Adam has 8 times as many red stickers as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Red |
Blue |
Before |
3 x 8 = 24 u |
1 x 8 = 8 u |
Change |
No Change |
- 25 |
After |
8 x 3 = 24 u |
1 x 3 = 3 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and blue stickers the same using LCM of 3 and 8.
LCM of 3 and 8 = 24
Number of blue stickers that Adam gives away
= 8 u - 3 u
= 5 u
5 u = 25
1 u = 25 ÷ 5 = 5
Number of more red stickers than blue stickers at first
= 24 u - 8 u
= 16 u
= 16 x 5
= 80
(b)
Number of less blue stickers than red stickers in the end
= 24 u - 3 u
= 21 u
= 21 x 5
= 105
Answer(s): (a) 80; (b) 105