Adam has 2 times as many blue stickers as green stickers.
After he gives away 27 green stickers,
Adam has 5 times as many blue stickers as green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many less green stickers than blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
2 x 5 = 10 u |
1 x 5 = 5 u |
Change |
No Change |
- 27 |
After |
5 x 2 = 10 u |
1 x 2 = 2 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and green stickers the same using LCM of 2 and 5.
LCM of 2 and 5 = 10
Number of green stickers that Adam gives away
= 5 u - 2 u
= 3 u
3 u = 27
1 u = 27 ÷ 3 = 9
Number of more blue stickers than green stickers at first
= 10 u - 5 u
= 5 u
= 5 x 9
= 45
(b)
Number of less green stickers than blue stickers in the end
= 10 u - 2 u
= 8 u
= 8 x 9
= 72
Answer(s): (a) 45; (b) 72