Adam has 5 times as many blue stickers as red stickers.
After he gives away 44 red stickers,
Adam has 9 times as many blue stickers as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Blue |
Red |
Before |
5 x 9 = 45 u |
1 x 9 = 9 u |
Change |
No Change |
- 44 |
After |
9 x 5 = 45 u |
1 x 5 = 5 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and red stickers the same using LCM of 5 and 9.
LCM of 5 and 9 = 45
Number of red stickers that Adam gives away
= 9 u - 5 u
= 4 u
4 u = 44
1 u = 44 ÷ 4 = 11
Number of more blue stickers than red stickers at first
= 45 u - 9 u
= 36 u
= 36 x 11
= 396
(b)
Number of less red stickers than blue stickers in the end
= 45 u - 5 u
= 40 u
= 40 x 11
= 440
Answer(s): (a) 396; (b) 440