Adam has 3 times as many green stickers as blue stickers.
After he gives away 20 blue stickers,
Adam has 8 times as many green stickers as blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many less blue stickers than green stickers does Adam have in the end?
|
Green |
Blue |
Before |
3 x 8 = 24 u |
1 x 8 = 8 u |
Change |
No Change |
- 20 |
After |
8 x 3 = 24 u |
1 x 3 = 3 u |
(a)
The number of green stickers remains unchanged.
Make the number of green stickers and blue stickers the same using LCM of 3 and 8.
LCM of 3 and 8 = 24
Number of blue stickers that Adam gives away
= 8 u - 3 u
= 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
Number of more green stickers than blue stickers at first
= 24 u - 8 u
= 16 u
= 16 x 4
= 64
(b)
Number of less blue stickers than green stickers in the end
= 24 u - 3 u
= 21 u
= 21 x 4
= 84
Answer(s): (a) 64; (b) 84