Adam has 5 times as many red stickers as blue stickers.
After he gives away 20 blue stickers,
Adam has 6 times as many red stickers as blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many less blue stickers than red stickers does Adam have in the end?
|
Red |
Blue |
Before |
5 x 6 = 30 u |
1 x 6 = 6 u |
Change |
No Change |
- 20 |
After |
6 x 5 = 30 u |
1 x 5 = 5 u |
(a)
The number of red stickers remains unchanged.
Make the number of red stickers and blue stickers the same using LCM of 5 and 6.
LCM of 5 and 6 = 30
Number of blue stickers that Adam gives away
= 6 u - 5 u
= 1 u
1 u = 20
Number of more red stickers than blue stickers at first
= 30 u - 6 u
= 24 u
= 24 x 20
= 480
(b)
Number of less blue stickers than red stickers in the end
= 30 u - 5 u
= 25 u
= 25 x 20
= 500
Answer(s): (a) 480; (b) 500