Adam has 2 times as many blue stickers as red stickers.
After he gives away 21 red stickers,
Adam has 3 times as many blue stickers as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Blue |
Red |
Before |
2 x 3 = 6 u |
1 x 3 = 3 u |
Change |
No Change |
- 21 |
After |
3 x 2 = 6 u |
1 x 2 = 2 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and red stickers the same using LCM of 2 and 3.
LCM of 2 and 3 = 6
Number of red stickers that Adam gives away
= 3 u - 2 u
= 1 u
1 u = 21
Number of more blue stickers than red stickers at first
= 6 u - 3 u
= 3 u
= 3 x 21
= 63
(b)
Number of less red stickers than blue stickers in the end
= 6 u - 2 u
= 4 u
= 4 x 21
= 84
Answer(s): (a) 63; (b) 84