Adam has 4 times as many blue stickers as red stickers.
After he gives away 47 red stickers,
Adam has 6 times as many blue stickers as red stickers.
- How many more blue stickers than red stickers does Adam have at first?
- How many less red stickers than blue stickers does Adam have in the end?
|
Blue |
Red |
Before |
4 x 3 = 12 u |
1 x 3 = 3 u |
Change |
No Change |
- 47 |
After |
6 x 2 = 12 u |
1 x 2 = 2 u |
(a)
The number of blue stickers remains unchanged.
Make the number of blue stickers and red stickers the same using LCM of 4 and 6.
LCM of 4 and 6 = 12
Number of red stickers that Adam gives away
= 3 u - 2 u
= 1 u
1 u = 47
1 u = 47 ÷ 1 = 47
Number of more blue stickers than red stickers at first
= 12 u - 6 u
= 6 u
= 6 x 47
= 282
(b)
Number of less red stickers than blue stickers in the end
= 12 u - 4 u
= 8 u
= 8 x 47
= 376
Answer(s): (a) 282; (b) 376