Adam has 2 times as many green stickers as blue stickers.
After he gives away 25 blue stickers,
Adam has 7 times as many green stickers as blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many less blue stickers than green stickers does Adam have in the end?
|
Green |
Blue |
Before |
2 x 7 = 14 u |
1 x 7 = 7 u |
Change |
No Change |
- 25 |
After |
7 x 2 = 14 u |
1 x 2 = 2 u |
(a)
The number of green stickers remains unchanged.
Make the number of green stickers and blue stickers the same using LCM of 2 and 7.
LCM of 2 and 7 = 14
Number of blue stickers that Adam gives away
= 7 u - 2 u
= 5 u
5 u = 25
1 u = 25 ÷ 5 = 5
Number of more green stickers than blue stickers at first
= 14 u - 7 u
= 7 u
= 7 x 5
= 35
(b)
Number of less blue stickers than green stickers in the end
= 14 u - 2 u
= 12 u
= 12 x 5
= 60
Answer(s): (a) 35; (b) 60