Adam has 3 times as many red stickers as blue stickers.
He buys another 180 blue stickers.
Adam has equal number of red and blue stickers.
- How many more red stickers than blue stickers does Adam have at first?
- How many blue stickers and red stickers does Adam have in the end?
|
Red |
Blue |
Before |
3 x 1 = 3 u |
1 x 1 = 1 u |
Change |
No Change |
+ 180 |
After |
1 × 3 = 3 u |
1 × 3 = 3 u |
(a)
The number of red stickers Adam has at first and in the end remains unchanged.
Make the number of red stickers the same using the LCM of 1 and 3.
LCM of 1 and 3 = 3
Number of blue stickers that Adam buys
= 3 u - 1 u
= 2 u
2 u = 180
1 u = 180 ÷ 2 = 90
Number of more red stickers than blue stickers at first
= 3 u - 1 u
= 2 u
= 2 x 90
= 180
(b)
Number of blue stickers and red stickers in the end
= 3 u + 3 u
= 6 u
= 6 × 90
= 540
Answer(s): (a) 180; (b) 540