Adam has 5 times as many red stickers as green stickers.
He buys another 120 green stickers.
Adam has equal number of red and green stickers.
- How many more red stickers than green stickers does Adam have at first?
- How many green stickers and red stickers does Adam have in the end?
|
Red |
Green |
Before |
5 x 1 = 5 u |
1 x 1 = 1 u |
Change |
No Change |
+ 120 |
After |
1 × 5 = 5 u |
1 × 5 = 5 u |
(a)
The number of red stickers Adam has at first and in the end remains unchanged.
Make the number of red stickers the same using the LCM of 1 and 5.
LCM of 1 and 5 = 5
Number of green stickers that Adam buys
= 5 u - 1 u
= 4 u
4 u = 120
1 u = 120 ÷ 4 = 30
Number of more red stickers than green stickers at first
= 5 u - 1 u
= 4 u
= 4 x 30
= 120
(b)
Number of green stickers and red stickers in the end
= 5 u + 5 u
= 10 u
= 10 × 30
= 300
Answer(s): (a) 120; (b) 300