Adam has 4 times as many green stickers as red stickers.
He buys another 150 red stickers.
Adam has equal number of green and red stickers.
- How many more green stickers than red stickers does Adam have at first?
- How many red stickers and green stickers does Adam have in the end?
|
Green |
Red |
Before |
4 x 1 = 4 u |
1 x 1 = 1 u |
Change |
No Change |
+ 150 |
After |
1 × 4 = 4 u |
1 × 4 = 4 u |
(a)
The number of green stickers Adam has at first and in the end remains unchanged.
Make the number of green stickers the same using the LCM of 1 and 4.
LCM of 1 and 4 = 4
Number of red stickers that Adam buys
= 4 u - 1 u
= 3 u
3 u = 150
1 u = 150 ÷ 3 = 50
Number of more green stickers than red stickers at first
= 4 u - 1 u
= 3 u
= 3 x 50
= 150
(b)
Number of red stickers and green stickers in the end
= 4 u + 4 u
= 8 u
= 8 × 50
= 400
Answer(s): (a) 150; (b) 400