Adam has 4 times as many blue stickers as green stickers.
He buys another 30 green stickers.
Adam has equal number of blue and green stickers.
- How many more blue stickers than green stickers does Adam have at first?
- How many green stickers and blue stickers does Adam have in the end?
|
Blue |
Green |
Before |
4 x 1 = 4 u |
1 x 1 = 1 u |
Change |
No Change |
+ 30 |
After |
1 × 4 = 4 u |
1 × 4 = 4 u |
(a)
The number of blue stickers Adam has at first and in the end remains unchanged.
Make the number of blue stickers the same using the LCM of 1 and 4.
LCM of 1 and 4 = 4
Number of green stickers that Adam buys
= 4 u - 1 u
= 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Number of more blue stickers than green stickers at first
= 4 u - 1 u
= 3 u
= 3 x 10
= 30
(b)
Number of green stickers and blue stickers in the end
= 4 u + 4 u
= 8 u
= 8 × 10
= 80
Answer(s): (a) 30; (b) 80