Adam has 10 times as many green stickers as blue stickers.
He buys another 180 blue stickers.
Adam has equal number of green and blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many blue stickers and green stickers does Adam have in the end?
|
Green |
Blue |
Before |
10 x 1 = 10 u |
1 x 1 = 1 u |
Change |
No Change |
+ 180 |
After |
1 × 10 = 10 u |
1 × 10 = 10 u |
(a)
The number of green stickers Adam has at first and in the end remains unchanged.
Make the number of green stickers the same using the LCM of 1 and 10.
LCM of 1 and 10 = 10
Number of blue stickers that Adam buys
= 10 u - 1 u
= 9 u
9 u = 180
1 u = 180 ÷ 9 = 20
Number of more green stickers than blue stickers at first
= 10 u - 1 u
= 9 u
= 9 x 20
= 180
(b)
Number of blue stickers and green stickers in the end
= 10 u + 10 u
= 20 u
= 20 × 20
= 400
Answer(s): (a) 180; (b) 400