Adam has 6 times as many green stickers as blue stickers.
He buys another 60 blue stickers.
Adam has equal number of green and blue stickers.
- How many more green stickers than blue stickers does Adam have at first?
- How many blue stickers and green stickers does Adam have in the end?
|
Green |
Blue |
Before |
6 x 1 = 6 u |
1 x 1 = 1 u |
Change |
No Change |
+ 60 |
After |
1 × 6 = 6 u |
1 × 6 = 6 u |
(a)
The number of green stickers Adam has at first and in the end remains unchanged.
Make the number of green stickers the same using the LCM of 1 and 6.
LCM of 1 and 6 = 6
Number of blue stickers that Adam buys
= 6 u - 1 u
= 5 u
5 u = 60
1 u = 60 ÷ 5 = 12
Number of more green stickers than blue stickers at first
= 6 u - 1 u
= 5 u
= 5 x 12
= 60
(b)
Number of blue stickers and green stickers in the end
= 6 u + 6 u
= 12 u
= 12 × 12
= 144
Answer(s): (a) 60; (b) 144