Adam has 3 times as many red stickers as green stickers.
He buys another 110 green stickers.
Adam has equal number of red and green stickers.
- How many more red stickers than green stickers does Adam have at first?
- How many green stickers and red stickers does Adam have in the end?
|
Red |
Green |
Before |
3 x 1 = 3 u |
1 x 1 = 1 u |
Change |
No Change |
+ 110 |
After |
1 × 3 = 3 u |
1 × 3 = 3 u |
(a)
The number of red stickers Adam has at first and in the end remains unchanged.
Make the number of red stickers the same using the LCM of 1 and 3.
LCM of 1 and 3 = 3
Number of green stickers that Adam buys
= 3 u - 1 u
= 2 u
2 u = 110
1 u = 110 ÷ 2 = 55
Number of more red stickers than green stickers at first
= 3 u - 1 u
= 2 u
= 2 x 55
= 110
(b)
Number of green stickers and red stickers in the end
= 3 u + 3 u
= 6 u
= 6 × 55
= 330
Answer(s): (a) 110; (b) 330