There are 95 stickers in Container B and 40 stickers in Container C.
Some stickers are transferred from Container B to Container C.
Container B has 25 more stickers than Container C.
How many stickers are transferred from Container B to Container C?
|
Container B |
Container C |
Before |
95 |
40 |
Change |
- ? |
+ ? |
After |
1 u + 25 |
1 u |
Total number of stickers
= 95 + 40
= 135
Total number of stickers in the end = 1 u + 25 + 1 u = 2 u + 25
The total number of stickers at first and in the end remains unchanged.
2 u + 25 = 135
2 u = 135 - 25 = 110
1 u = 110 ÷ 2 = 55
Number of stickers that are transferred from Container B to Container C
= Number of stickers in Container C in the end - Number of stickers in Container C at first
= 55 - 40
= 15
Answer(s): 15