There are 100 stickers in Box D and 15 stickers in Box E.
Some stickers are transferred from Box D to Box E.
Box D has 5 more stickers than Box E.
How many stickers are transferred from Box D to Box E?
|
Box D |
Box E |
Before |
100 |
15 |
Change |
- ? |
+ ? |
After |
1 u + 5 |
1 u |
Total number of stickers
= 100 + 15
= 115
Total number of stickers in the end = 1 u + 5 + 1 u = 2 u + 5
The total number of stickers at first and in the end remains unchanged.
2 u + 5 = 115
2 u = 115 - 5 = 110
1 u = 110 ÷ 2 = 55
Number of stickers that are transferred from Box D to Box E
= Number of stickers in Box E in the end - Number of stickers in Box E at first
= 55 - 15
= 40
Answer(s): 40