There are 100 stickers in Container X and 80 stickers in Container Y.
Some stickers are transferred from Container X to Container Y.
Container Y has 70 more stickers than Container X.
How many stickers are transferred from Container X to Container Y?
|
Container X |
Container Y |
Before |
100 |
80 |
Change |
- ? |
+ ? |
After |
1 u |
1 u + 70 |
Total number of stickers
= 100 + 80
= 180
In the end
Total number of stickers = 1 u + 1 u + 70 = 2 u + 70
The total number of stickers at first and in the end remains unchanged.
2 u + 70 = 180
2 u = 180 - 70 = 110
1 u = 110 ÷ 2 = 55
Number of stickers that are transferred from Container X to Container Y
= Number of stickers in Container X at first - Number of stickers in Container X in the end
= 100 - 55
= 45
Answer(s): 45