There are 95 stickers in Box Y and 40 stickers in Box Z.
Some stickers are transferred from Box Y to Box Z.
Box Z has 15 more stickers than Box Y.
How many stickers are transferred from Box Y to Box Z?
|
Box Y |
Box Z |
Before |
95 |
40 |
Change |
- ? |
+ ? |
After |
1 u |
1 u + 15 |
Total number of stickers
= 95 + 40
= 135
In the end
Total number of stickers = 1 u + 1 u + 15 = 2 u + 15
The total number of stickers at first and in the end remains unchanged.
2 u + 15 = 135
2 u = 135 - 15 = 120
1 u = 120 ÷ 2 = 60
Number of stickers that are transferred from Box Y to Box Z
= Number of stickers in Box Y at first - Number of stickers in Box Y in the end
= 95 - 60
= 35
Answer(s): 35