Bryan and Adam have $70.
Bryan has 6 times as much money as Adam.
How much must Bryan give to Adam
so Bryan will have $10 less than Adam?
|
Bryan |
Adam |
Total |
Before |
6 u |
1 u |
7 u |
Change |
- ? |
+ ? |
No change |
After |
$30 |
$30 + $10 |
$70 |
At first
Bryan = 6 u
Adam = 1 u
Total = 1 u + 6 u = 7 u
7 u = 70
1 u = 70 ÷ 7 = 10
Amount that Bryan has at first
= 6 u
= 6 x 10
= $60
For Bryan to have $10 less than Adam in the end, we need to set aside $10 for Adam before the remaining amount is divided into 2.
Amount that Bryan will have in the end
= (70 - 10) ÷ 2
= 60 ÷ 2
= $30
Amount that Bryan gives to Adam
= Amount that Bryan at first - Amount that Bryan has in the end
= 60 - 30
= $30
Answer(s): $30