Adam and Bryan have $30.
Adam has 9 times as much money as Bryan.
How much must Adam give to Bryan
so Adam will have $10 less than Bryan?
|
Adam |
Bryan |
Total |
Before |
9 u |
1 u |
10 u |
Change |
- ? |
+ ? |
No change |
After |
$10 |
$10 + $10 |
$30 |
At first
Adam = 9 u
Bryan = 1 u
Total = 1 u + 9 u = 10 u
10 u = 30
1 u = 30 ÷ 10 = 3
Amount that Adam has at first
= 9 u
= 9 x 3
= $27
For Adam to have $10 less than Bryan in the end, we need to set aside $10 for Bryan before the remaining amount is divided into 2.
Amount that Adam will have in the end
= (30 - 10) ÷ 2
= 20 ÷ 2
= $10
Amount that Adam gives to Bryan
= Amount that Adam at first - Amount that Adam has in the end
= 27 - 10
= $17
Answer(s): $17