Bryan and Adam have $90.
Bryan has 8 times as much money as Adam.
How much must Bryan give to Adam
so Bryan will have $60 less than Adam?
|
Bryan |
Adam |
Total |
Before |
8 u |
1 u |
9 u |
Change |
- ? |
+ ? |
No change |
After |
$15 |
$15 + $60 |
$90 |
At first
Bryan = 8 u
Adam = 1 u
Total = 1 u + 8 u = 9 u
9 u = 90
1 u = 90 ÷ 9 = 10
Amount that Bryan has at first
= 8 u
= 8 x 10
= $80
For Bryan to have $60 less than Adam in the end, we need to set aside $60 for Adam before the remaining amount is divided into 2.
Amount that Bryan will have in the end
= (90 - 60) ÷ 2
= 30 ÷ 2
= $15
Amount that Bryan gives to Adam
= Amount that Bryan at first - Amount that Bryan has in the end
= 80 - 15
= $65
Answer(s): $65