Adam and Bryan have $90.
Adam has 8 times as much money as Bryan.
How much must Adam give to Bryan
so Adam will have $80 less than Bryan?
| |
Adam |
Bryan |
Total |
| Before |
8 u |
1 u |
9 u |
| Change |
- ? |
+ ? |
No change |
| After |
$5 |
$5 + $80 |
$90 |
At first
Adam = 8 u
Bryan = 1 u
Total = 1 u + 8 u = 9 u
9 u = 90
1 u = 90 ÷ 9 = 10
Amount that Adam has at first
= 8 u
= 8 x 10
= $80
For Adam to have $80 less than Bryan in the end, we need to set aside $80 for Bryan before the remaining amount is divided into 2.
Amount that Adam will have in the end
= (90 - 80) ÷ 2
= 10 ÷ 2
= $5
Amount that Adam gives to Bryan
= Amount that Adam at first - Amount that Adam has in the end
= 80 - 5
= $75
Answer(s): $75
