Bryan and Adam have $30.
Bryan has 2 times as much money as Adam.
How much must Bryan give to Adam
so Bryan will have $10 less than Adam?
| |
Bryan |
Adam |
Total |
| Before |
2 u |
1 u |
3 u |
| Change |
- ? |
+ ? |
No change |
| After |
$10 |
$10 + $10 |
$30 |
At first
Bryan = 2 u
Adam = 1 u
Total = 1 u + 2 u = 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Amount that Bryan has at first
= 2 u
= 2 x 10
= $20
For Bryan to have $10 less than Adam in the end, we need to set aside $10 for Adam before the remaining amount is divided into 2.
Amount that Bryan will have in the end
= (30 - 10) ÷ 2
= 20 ÷ 2
= $10
Amount that Bryan gives to Adam
= Amount that Bryan at first - Amount that Bryan has in the end
= 20 - 10
= $10
Answer(s): $10
