Bryan and Adam have $100.
Bryan has 9 times as much money as Adam.
How much must Bryan give to Adam
so Bryan will have $90 less than Adam?
| |
Bryan |
Adam |
Total |
| Before |
9 u |
1 u |
10 u |
| Change |
- ? |
+ ? |
No change |
| After |
$5 |
$5 + $90 |
$100 |
At first
Bryan = 9 u
Adam = 1 u
Total = 1 u + 9 u = 10 u
10 u = 100
1 u = 100 ÷ 10 = 10
Amount that Bryan has at first
= 9 u
= 9 x 10
= $90
For Bryan to have $90 less than Adam in the end, we need to set aside $90 for Adam before the remaining amount is divided into 2.
Amount that Bryan will have in the end
= (100 - 90) ÷ 2
= 10 ÷ 2
= $5
Amount that Bryan gives to Adam
= Amount that Bryan at first - Amount that Bryan has in the end
= 90 - 5
= $85
Answer(s): $85
