Adam and Bryan have $80.
Adam has 9 times as much money as Bryan.
How much must Adam give to Bryan
so Adam will have $50 less than Bryan?
| |
Adam |
Bryan |
Total |
| Before |
9 u |
1 u |
10 u |
| Change |
- ? |
+ ? |
No change |
| After |
$15 |
$15 + $50 |
$80 |
At first
Adam = 9 u
Bryan = 1 u
Total = 1 u + 9 u = 10 u
10 u = 80
1 u = 80 ÷ 10 = 8
Amount that Adam has at first
= 9 u
= 9 x 8
= $72
For Adam to have $50 less than Bryan in the end, we need to set aside $50 for Bryan before the remaining amount is divided into 2.
Amount that Adam will have in the end
= (80 - 50) ÷ 2
= 30 ÷ 2
= $15
Amount that Adam gives to Bryan
= Amount that Adam at first - Amount that Adam has in the end
= 72 - 15
= $57
Answer(s): $57
