Bryan and Adam have $80.
Bryan has 9 times as much money as Adam.
How much must Bryan give to Adam
so Bryan will have $10 less than Adam?
|
Bryan |
Adam |
Total |
Before |
9 u |
1 u |
10 u |
Change |
- ? |
+ ? |
No change |
After |
$35 |
$35 + $10 |
$80 |
At first
Bryan = 9 u
Adam = 1 u
Total = 1 u + 9 u = 10 u
10 u = 80
1 u = 80 ÷ 10 = 8
Amount that Bryan has at first
= 9 u
= 9 x 8
= $72
For Bryan to have $10 less than Adam in the end, we need to set aside $10 for Adam before the remaining amount is divided into 2.
Amount that Bryan will have in the end
= (80 - 10) ÷ 2
= 70 ÷ 2
= $35
Amount that Bryan gives to Adam
= Amount that Bryan at first - Amount that Bryan has in the end
= 72 - 35
= $37
Answer(s): $37