Adam and Bryan have $80.
Adam has 7 times as much money as Bryan.
How much must Adam give to Bryan
so Adam will have $20 less than Bryan?
| |
Adam |
Bryan |
Total |
| Before |
7 u |
1 u |
8 u |
| Change |
- ? |
+ ? |
No change |
| After |
$30 |
$30 + $20 |
$80 |
At first
Adam = 7 u
Bryan = 1 u
Total = 1 u + 7 u = 8 u
8 u = 80
1 u = 80 ÷ 8 = 10
Amount that Adam has at first
= 7 u
= 7 x 10
= $70
For Adam to have $20 less than Bryan in the end, we need to set aside $20 for Bryan before the remaining amount is divided into 2.
Amount that Adam will have in the end
= (80 - 20) ÷ 2
= 60 ÷ 2
= $30
Amount that Adam gives to Bryan
= Amount that Adam at first - Amount that Adam has in the end
= 70 - 30
= $40
Answer(s): $40
