Adam and Bryan have $40.
Adam has 9 times as much money as Bryan.
How much must Adam give to Bryan
so Adam will have $30 less than Bryan?
|
Adam |
Bryan |
Total |
Before |
9 u |
1 u |
10 u |
Change |
- ? |
+ ? |
No change |
After |
$5 |
$5 + $30 |
$40 |
At first
Adam = 9 u
Bryan = 1 u
Total = 1 u + 9 u = 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Amount that Adam has at first
= 9 u
= 9 x 4
= $36
For Adam to have $30 less than Bryan in the end, we need to set aside $30 for Bryan before the remaining amount is divided into 2.
Amount that Adam will have in the end
= (40 - 30) ÷ 2
= 10 ÷ 2
= $5
Amount that Adam gives to Bryan
= Amount that Adam at first - Amount that Adam has in the end
= 36 - 5
= $31
Answer(s): $31