Bryan and Adam have $30.
Bryan has 9 times as much money as Adam.
How much must Bryan give to Adam
so Bryan will have $10 less than Adam?
|
Bryan |
Adam |
Total |
Before |
9 u |
1 u |
10 u |
Change |
- ? |
+ ? |
No change |
After |
$10 |
$10 + $10 |
$30 |
At first
Bryan = 9 u
Adam = 1 u
Total = 1 u + 9 u = 10 u
10 u = 30
1 u = 30 ÷ 10 = 3
Amount that Bryan has at first
= 9 u
= 9 x 3
= $27
For Bryan to have $10 less than Adam in the end, we need to set aside $10 for Adam before the remaining amount is divided into 2.
Amount that Bryan will have in the end
= (30 - 10) ÷ 2
= 20 ÷ 2
= $10
Amount that Bryan gives to Adam
= Amount that Bryan at first - Amount that Bryan has in the end
= 27 - 10
= $17
Answer(s): $17