Bryan and Adam have $40.
Bryan has 3 times as much money as Adam.
How much must Bryan give to Adam
so Bryan will have $20 less than Adam?
|
Bryan |
Adam |
Total |
Before |
3 u |
1 u |
4 u |
Change |
- ? |
+ ? |
No change |
After |
$10 |
$10 + $20 |
$40 |
At first
Bryan = 3 u
Adam = 1 u
Total = 1 u + 3 u = 4 u
4 u = 40
1 u = 40 ÷ 4 = 10
Amount that Bryan has at first
= 3 u
= 3 x 10
= $30
For Bryan to have $20 less than Adam in the end, we need to set aside $20 for Adam before the remaining amount is divided into 2.
Amount that Bryan will have in the end
= (40 - 20) ÷ 2
= 20 ÷ 2
= $10
Amount that Bryan gives to Adam
= Amount that Bryan at first - Amount that Bryan has in the end
= 30 - 10
= $20
Answer(s): $20