Bryan and Adam have $40.
Bryan has 7 times as much money as Adam.
How much must Bryan give to Adam
so Bryan will have $30 less than Adam?
| |
Bryan |
Adam |
Total |
| Before |
7 u |
1 u |
8 u |
| Change |
- ? |
+ ? |
No change |
| After |
$5 |
$5 + $30 |
$40 |
At first
Bryan = 7 u
Adam = 1 u
Total = 1 u + 7 u = 8 u
8 u = 40
1 u = 40 ÷ 8 = 5
Amount that Bryan has at first
= 7 u
= 7 x 5
= $35
For Bryan to have $30 less than Adam in the end, we need to set aside $30 for Adam before the remaining amount is divided into 2.
Amount that Bryan will have in the end
= (40 - 30) ÷ 2
= 10 ÷ 2
= $5
Amount that Bryan gives to Adam
= Amount that Bryan at first - Amount that Bryan has in the end
= 35 - 5
= $30
Answer(s): $30
