Adam and Bryan have $70.
Adam has 6 times as much money as Bryan.
How much must Adam give to Bryan
so Adam will have $20 less than Bryan?
| |
Adam |
Bryan |
Total |
| Before |
6 u |
1 u |
7 u |
| Change |
- ? |
+ ? |
No change |
| After |
$25 |
$25 + $20 |
$70 |
At first
Adam = 6 u
Bryan = 1 u
Total = 1 u + 6 u = 7 u
7 u = 70
1 u = 70 ÷ 7 = 10
Amount that Adam has at first
= 6 u
= 6 x 10
= $60
For Adam to have $20 less than Bryan in the end, we need to set aside $20 for Bryan before the remaining amount is divided into 2.
Amount that Adam will have in the end
= (70 - 20) ÷ 2
= 50 ÷ 2
= $25
Amount that Adam gives to Bryan
= Amount that Adam at first - Amount that Adam has in the end
= 60 - 25
= $35
Answer(s): $35
