Bryan and Adam have $60.
Bryan has 5 times as much money as Adam.
How much must Bryan give to Adam
so Bryan will have $20 less than Adam?
|
Bryan |
Adam |
Total |
Before |
5 u |
1 u |
6 u |
Change |
- ? |
+ ? |
No change |
After |
$20 |
$20 + $20 |
$60 |
At first
Bryan = 5 u
Adam = 1 u
Total = 1 u + 5 u = 6 u
6 u = 60
1 u = 60 ÷ 6 = 10
Amount that Bryan has at first
= 5 u
= 5 x 10
= $50
For Bryan to have $20 less than Adam in the end, we need to set aside $20 for Adam before the remaining amount is divided into 2.
Amount that Bryan will have in the end
= (60 - 20) ÷ 2
= 40 ÷ 2
= $20
Amount that Bryan gives to Adam
= Amount that Bryan at first - Amount that Bryan has in the end
= 50 - 20
= $30
Answer(s): $30