Adam and Bryan have $70.
Adam has 9 times as much money as Bryan.
How much must Adam give to Bryan
so Adam will have $10 less than Bryan?
|
Adam |
Bryan |
Total |
Before |
9 u |
1 u |
10 u |
Change |
- ? |
+ ? |
No change |
After |
$30 |
$30 + $10 |
$70 |
At first
Adam = 9 u
Bryan = 1 u
Total = 1 u + 9 u = 10 u
10 u = 70
1 u = 70 ÷ 10 = 7
Amount that Adam has at first
= 9 u
= 9 x 7
= $63
For Adam to have $10 less than Bryan in the end, we need to set aside $10 for Bryan before the remaining amount is divided into 2.
Amount that Adam will have in the end
= (70 - 10) ÷ 2
= 60 ÷ 2
= $30
Amount that Adam gives to Bryan
= Amount that Adam at first - Amount that Adam has in the end
= 63 - 30
= $33
Answer(s): $33