Adam and Bryan have a total of 1000 stickers.
Adam gives Bryan 500 stickers.
Now, they have the same number of stickers.
- How many stickers does Adam have at first?
- How many stickers does each have in the end?
|
Adam |
Bryan |
Total |
Before |
1 u + 500 |
1 u - 500 |
1000 |
Change |
- 500 |
+ 500 |
|
After |
1 u |
1 u |
2 u |
(a)
In the end
Number of stickers that Adam has = 1 u
Number of stickers that Bryan has = 1 u
Total number of stickers = 1 u + 1 u = 2 u
At first
Number of stickers that Adam has = 1 u + 500
Number of stickers that Bryan has = 1 u - 500
2 u = 1000
1 u = 1000 ÷ 2 = 500
Number of stickers that Adam has at first
= 1 u + 500
= 500 + 500
= 1000
(b)
Number of stickers that each has in the end
= 1 u
= 500
Answer(s): (a) 1000; (b) 500