Bryan and Adam have a total of 600 stickers.
Bryan gives Adam 20 stickers.
Now, Bryan has 50 more than Adam.
- How many stickers does Bryan have at first?
- How many stickers does Adam have in the end?
|
Bryan |
Adam |
Total |
Before |
1 u + 70 |
1 u - 20 |
600 |
Change |
- 20 |
+ 20 |
|
After |
1 u + 50 |
1 u |
2 u + 50 |
(a)
In the end
Number of stickers that Bryan has = 1 u + 50
Number of stickers that Adam has = 1 u
Total number of stickers = 1 u + 1 u + 50 = 2 u + 50
At first
Number of stickers that Bryan has = 1 u + 50 + 20 = 1 u + 70
Number of stickers that Adam has = 1 u - 20
The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first
2 u + 50 = 600
2 u = 600 - 50
2 u = 550
1 u = 550 ÷ 2 = 275
Number of stickers that Bryan has at first
= 1 u + 70
= 275 + 70
= 345
(b)
Number of stickers that Adam has in the end
= 1 u
= 275
Answer(s): (a) 345; (b) 275