Bryan and Adam have a total of 200 stickers.
Bryan gives Adam 10 stickers.
Now, Bryan has 20 more than Adam.
- How many stickers does Bryan have at first?
- How many stickers does Adam have in the end?
|
Bryan |
Adam |
Total |
Before |
1 u + 30 |
1 u - 10 |
200 |
Change |
- 10 |
+ 10 |
|
After |
1 u + 20 |
1 u |
2 u + 20 |
(a)
In the end
Number of stickers that Bryan has = 1 u + 20
Number of stickers that Adam has = 1 u
Total number of stickers = 1 u + 1 u + 20 = 2 u + 20
At first
Number of stickers that Bryan has = 1 u + 20 + 10 = 1 u + 30
Number of stickers that Adam has = 1 u - 10
The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first
2 u + 20 = 200
2 u = 200 - 20
2 u = 180
1 u = 180 ÷ 2 = 90
Number of stickers that Bryan has at first
= 1 u + 30
= 90 + 30
= 120
(b)
Number of stickers that Adam has in the end
= 1 u
= 90
Answer(s): (a) 120; (b) 90