Bryan and Adam have a total of 400 stickers.
Bryan gives Adam 20 stickers.
Now, Bryan has 70 more than Adam.
- How many stickers does Bryan have at first?
- How many stickers does Adam have in the end?
|
Bryan |
Adam |
Total |
Before |
1 u + 90 |
1 u - 20 |
400 |
Change |
- 20 |
+ 20 |
|
After |
1 u + 70 |
1 u |
2 u + 70 |
(a)
In the end
Number of stickers that Bryan has = 1 u + 70
Number of stickers that Adam has = 1 u
Total number of stickers = 1 u + 1 u + 70 = 2 u + 70
At first
Number of stickers that Bryan has = 1 u + 70 + 20 = 1 u + 90
Number of stickers that Adam has = 1 u - 20
The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first
2 u + 70 = 400
2 u = 400 - 70
2 u = 330
1 u = 330 ÷ 2 = 165
Number of stickers that Bryan has at first
= 1 u + 90
= 165 + 90
= 255
(b)
Number of stickers that Adam has in the end
= 1 u
= 165
Answer(s): (a) 255; (b) 165