Adam and Bryan have a total of 200 stickers.
Adam gives Bryan 10 stickers.
Now, Adam has 30 more than Bryan.

1. How many stickers does Adam have at first?
2. How many stickers does Bryan have in the end?

	Adam	Bryan	Total
Before	1 u + 40	1 u - 10	200
Change	- 10	+ 10
After	1 u + 30	1 u	2 u + 30

(a)
In the end
Number of stickers that Adam has = 1 u + 30
Number of stickers that Bryan has = 1 u
Total number of stickers = 1 u + 1 u + 30 = 2 u + 30

At first
Number of stickers that Adam has = 1 u + 30 + 10 = 1 u + 40
Number of stickers that Bryan has = 1 u - 10

The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first

2 u + 30 = 200
2 u = 200 - 30
2 u = 170

1 u = 170 ÷ 2 = 85

Number of stickers that Adam has at first
= 1 u + 40
= 85 + 40
= 125

(b)
Number of stickers that Bryan has in the end
= 1 u
= 85

Answer(s): (a) 125; (b) 85