Bryan and Adam have a total of 600 stickers.
Bryan gives Adam 10 stickers.
Now, Bryan has 30 more than Adam.
- How many stickers does Bryan have at first?
- How many stickers does Adam have in the end?
|
Bryan |
Adam |
Total |
Before |
1 u + 40 |
1 u - 10 |
600 |
Change |
- 10 |
+ 10 |
|
After |
1 u + 30 |
1 u |
2 u + 30 |
(a)
In the end
Number of stickers that Bryan has = 1 u + 30
Number of stickers that Adam has = 1 u
Total number of stickers = 1 u + 1 u + 30 = 2 u + 30
At first
Number of stickers that Bryan has = 1 u + 30 + 10 = 1 u + 40
Number of stickers that Adam has = 1 u - 10
The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first
2 u + 30 = 600
2 u = 600 - 30
2 u = 570
1 u = 570 ÷ 2 = 285
Number of stickers that Bryan has at first
= 1 u + 40
= 285 + 40
= 325
(b)
Number of stickers that Adam has in the end
= 1 u
= 285
Answer(s): (a) 325; (b) 285