Adam and Bryan have a total of 200 stickers.
Adam gives Bryan 10 stickers.
Now, Adam has 50 more than Bryan.
- How many stickers does Adam have at first?
- How many stickers does Bryan have in the end?
|
Adam |
Bryan |
Total |
Before |
1 u + 60 |
1 u - 10 |
200 |
Change |
- 10 |
+ 10 |
|
After |
1 u + 50 |
1 u |
2 u + 50 |
(a)
In the end
Number of stickers that Adam has = 1 u + 50
Number of stickers that Bryan has = 1 u
Total number of stickers = 1 u + 1 u + 50 = 2 u + 50
At first
Number of stickers that Adam has = 1 u + 50 + 10 = 1 u + 60
Number of stickers that Bryan has = 1 u - 10
The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first
2 u + 50 = 200
2 u = 200 - 50
2 u = 150
1 u = 150 ÷ 2 = 75
Number of stickers that Adam has at first
= 1 u + 60
= 75 + 60
= 135
(b)
Number of stickers that Bryan has in the end
= 1 u
= 75
Answer(s): (a) 135; (b) 75